The standard heat of formation, in kcal/mol of Ba$^{2+}$ is: [Given : standard heat of formation of SO$_4^{2-}$ ion (aq)= –216 kcal/mol, standard heat of crystallization of BaSO$_4$(s) = –4.5 kcal/mol, standard heat of formation of BaSO$_4$(s) = –349 kcal/mol]

Question

Dr. Abubacker · Accepted Answer

[Solution by Claude - not from source] $Ba^{2+}+SO_4^{2-}	o BaSO_4(s)$, $\Delta H=-4.5$. $\Delta_fH(BaSO_4)=\Delta_fH(Ba^{2+})+\Delta_fH(SO_4^{2-})-4.5$. $-349=x-216-4.5\Rightarrow x=-128.5$ kcal/mol. Answer (1).

Q. The standard heat of formation, in kcal/mol of Ba$^{2+}$ is: [Given : standard heat of formation of SO$_4^{2-}$ ion (aq)= –216 kcal/mol, standard heat of crystallization of BaSO$_4$(s) = –4.5 kcal/mol, standard heat of formation of BaSO$_4$(s) = –349 kcal/mol]

Explanation

Reviewed by Dr. Abubacker

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