If the rate constant of a reaction is 0.03 s$^{-1}$, how much time does it take for 7.2 mol L$^{-1}$ concentration of the reactant to get reduced to 0.9 mol L$^{-1}$? (Given : log 2 = 0.301)

Question

Dr. Abubacker · Accepted Answer

[Solution by Claude - not from source] $t=\frac{2.303}{k}\log\frac{7.2}{0.9}=\frac{2.303}{0.03}	imes3(0.301)\approx69.3$ s (3 half-lives of 23.1 s). Answer (1).

Q. If the rate constant of a reaction is 0.03 s$^{-1}$, how much time does it take for 7.2 mol L$^{-1}$ concentration of the reactant to get reduced to 0.9 mol L$^{-1}$? (Given : log 2 = 0.301)

Explanation

Reviewed by Dr. Abubacker

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