Q. In an ideal transformer, the turns ratio is $\frac{N_p}{N_s}=\frac{1}{2}$. The ratio $V_s:V_p$ is equal to (the symbols carry their usual meaning):
A) 1 : 1
B) 1 : 4
C) 1 : 2
D) 2 : 1
Explanation
[Solution by Claude - not from source] $\frac{V_s}{V_p}=\frac{N_s}{N_p}=2$, so $V_s:V_p=2:1$. Answer (4).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.