Q. The maximum elongation of a steel wire of 1 m length if the elastic limit of steel and its Young’s modulus, respectively, are $8 \times 10^8$ N m$^{-2}$ and $2 \times 10^{11}$ N m$^{-2}$, is:

A) 40 mm
B) 8 mm
C) 4 mm
D) 0.4 mm
Explanation

[Solution by Claude - not from source] $\Delta l=\frac{\text{stress}}{Y}L=\frac{8\times10^8}{2\times10^{11}}\times1=4\times10^{-3}$ m $=4$ mm. Answer (3).

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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