[Solution by Claude - not from source] Axial potential is $V=\pm\frac{P}{4\pi\epsilon_0r^2}=9\times10^9\times\frac{4\times10^{-6}}{4}=9\times10^3$ V, so A is true. The factor 2 in R belongs to the axial field, not the potential, so R is false. Answer (1).