Q. A bob is whirled in a horizontal plane by means of a string with an initial speed of $\omega$ rpm. The tension in the string is $T$. If speed becomes $2\,\omega$ white keeping the same radius, the tension in the string becomes;

A) $\frac{T}{4}$
B) $\sqrt2T$
C) $T$
D) $4T$
Explanation

[Solution by Claude - not from source] $T=m\omega^2r\propto\omega^2$, so doubling the speed gives $4T$. Answer (4).

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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