Q. A force defined by $F=\alpha t^2+\beta t$ acts on a particle at a given time $t$. The factor which is dimensionless, if $\alpha$ and $\beta$ are constants, is:

A) $\alpha\beta t$
B) $\frac{\alpha\beta}{t}$
C) $\frac{\beta t}{\alpha}$
D) $\frac{\alpha t}{\beta}$
Explanation

[Solution by Claude - not from source] $[\alpha t^2]=[\beta t]=[F]$, so $\frac{\alpha t}{\beta}$ is dimensionless. Answer (4).

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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