Q.
A small telescope has an objective of focal length 140 cm and an eye piece of focal length 5.0 cm. The magnifying power of telescope for viewing a distant object is:
A) 17
B) 32
C) 34
D) 28
Explanation
[Solution by Claude - not from source] $m=\frac{f_o}{f_e}=\frac{140}{5}=28$. Answer (4).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.