Q. If the mass of the bob in simple pendulum is increased to thrice its original mass and its length is made half its original length, then the new time period of oscillation is $\frac{x}{2}$ times its original time period. Then the value of $x$ is:
A) $2\sqrt3$
B) 4
C) $\sqrt3$
D) $\sqrt2$
Explanation
[Solution by Claude - not from source] $T=2\pi\sqrt{l/g}$ is independent of mass; halving $l$ gives $T'=T/\sqrt2=\frac x2T\Rightarrow x=\sqrt2$. Answer (4).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.