Q. The minimum energy required to launch a satellite of mass $m$ from the surface of earth of mass $M$ and radius $R$ in a circular orbit at an altitude of $2R$ from the surface of the earth is:
A) $\frac{GmM}{2R}$
B) $\frac{GmM}{3R}$
C) $\frac{5GmM}{6R}$
D) $\frac{2GmM}{3R}$
Explanation
[Solution by Claude - not from source] Orbit radius $3R$. $E=-\frac{GMm}{6R}-\left(-\frac{GMm}{R}\right)=\frac{5GMm}{6R}$. Answer (3).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.