Q. Match List-I with List-II. [table] List-I (Conversion) | List-II (Number of Faraday required) ; A. 1 mol of H$_2$O to O$_2$ | I. 3F ; B. 1 mol of MnO$_4^-$ to Mn$^{2+}$ | II. 2F ; C. 1.5 mol of Ca from molten CaCl$_2$ | III. 1F ; D. 1 mol of FeO to Fe$_2$O$_3$ | IV. 5F [/table] Choose the correct answer from the options given below:
A) A-II, B-III, C-I, D-IV
B) A-III, B-IV, C-II, D-I
C) A-II, B-IV, C-I, D-III
D) A-III, B-IV, C-I, D-II
Explanation
[Solution by Claude - not from source] A: $H_2O\to\frac12O_2$ needs $2e^-$ (2F). B: $Mn^{7+}\to Mn^{2+}$ needs 5F. C: $1.5\times2=3$F. D: $Fe^{2+}\to Fe^{3+}$ needs 1F. Answer (3).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.