Q. 1 gram of sodium hydroxide was treated with 25 mL of 0.75 M HCl solution, the mass of sodium hydroxide left unreacted is equal to
A) Zero mg
B) 200 mg
C) 750 mg
D) 250 mg
Explanation
[Solution by Claude - not from source] NaOH $=1/40=0.025$ mol; HCl $=0.01875$ mol. Left $=0.00625$ mol $\times40=0.25$ g $=250$ mg. Answer (4).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.