Q. Activation energy of any chemical reaction can be calculated if one knows the value of
A) orientation of reactant molecules during collision.
B) rate constant at two different temperatures.
C) rate constant at standard temperature.
D) probability of collision.
Explanation
[Solution by Claude - not from source] Arrhenius equation: $\log\frac{k_2}{k_1}=\frac{E_a}{2.303R}\left(\frac1{T_1}-\frac1{T_2}\right)$. Answer (2).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.