The energy of an electron in the ground state ($n=1$) for $He^+$ ion is $-x$ J, then that for an electron in $n=2$ state for $Be^{3+}$ ion in J is:

Question

Dr. Abubacker · Accepted Answer

[Solution by Claude - not from source] $E\propto\frac{Z^2}{n^2}$. $He^+$ ($n=1$): $4$; $Be^{3+}$ ($n=2$): $\frac{16}{4}=4$. So the energy is $-x$. Answer (3).

Q. The energy of an electron in the ground state ($n=1$) for $He^+$ ion is $-x$ J, then that for an electron in $n=2$ state for $Be^{3+}$ ion in J is:

Explanation

Reviewed by Dr. Abubacker

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