Q. Match List-I with List-II [table] List-I (Complex) | List-II (Type of isomerism) ; A. $[Co(NH_3)_5(NO_2)]Cl_2$ | I. Solvate isomerism ; B. $[Co(NH_3)_5(SO_4)]Br$ | II. Linkage isomerism ; C. $[Co(NH_3)_6][Cr(CN)_6]$ | III. Ionization isomerism ; D. $[Co(H_2O)_6]Cl_3$ | IV. Coordination isomerism [/table] Choose the correct answer from the options given below:
A) A-I, B-IV, C-III, D-II
B) A-II, B-IV, C-III, D-I
C) A-II, B-III, C-IV, D-I
D) A-I, B-III, C-IV, D-II
Explanation
[Solution by Claude - not from source] $NO_2^-$ is ambidentate (linkage); $SO_4^{2-}/Br^-$ exchange (ionization); two complex ions exchanging ligands (coordination); hydrate $[Co(H_2O)_6]Cl_3$ (solvate). Answer (3).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.