The Henry’s law constant ($K_H$) values of three gases (A, B, C) in water are 145, $2 imes10^{-5}$ and 35 kbar, respectively. The solubility of these gases in water follow the order:

Question

The Henry’s law constant ($K_H$) values of three gases (A, B, C) in water are 145, $2	imes10^{-5}$ and 35 kbar, respectively. The solubility of these gases in water follow the order:

Dr. Abubacker · Accepted Answer

[Solution by Claude - not from source] Solubility is inversely proportional to $K_H$: B ($2	imes10^{-5}$) > C (35) > A (145). Answer (4).

Q. The Henry’s law constant ($K_H$) values of three gases (A, B, C) in water are 145, $2\times10^{-5}$ and 35 kbar, respectively. The solubility of these gases in water follow the order:

Explanation

Reviewed by Dr. Abubacker

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