Q. A compound X contains 32% of A, 20% of B and remaining percentage of C. Then, the empirical formula of X is: (Given atomic masses of A = 64; B = 40; C = 32u)
A) $AB_2C_2$
B) $ABC_4$
C) $A_2BC_2$
D) $ABC_3$
Explanation
[Solution by Claude - not from source] C $=48\%$. Moles: A $0.5$, B $0.5$, C $1.5$, giving ratio $1:1:3$, so $ABC_3$. Answer (4).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.