Q. Mass in grams of copper deposited by passing 9.6487 A current through a voltmeter containing copper sulphate solution for 100 seconds is: (Given: Molar mass of Cu : 63 g mol$^{-1}$, 1F = 96487 C)
A) 31.5 g
B) 0.0315 g
C) 3.15 g
D) 0.315 g
Explanation
[Solution by Claude - not from source] $Q=964.87$ C $=0.01$ F; $Cu^{2+}+2e^-\to Cu$ gives $0.005$ mol $\times63=0.315$ g. Answer (4).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.