Q. Match List-I with List-II. [table] List-I (Products formed) | List-II (Reaction of carbonyl compound with) ; (a) Cyanohydrin | (i) $NH_2OH$ ; (b) Acetal | (ii) $RNH_2$ ; (c) Schiff's base | (iii) alcohol ; (d) Oxime | (iv) HCN [/table] Choose the correct answer from the options given belwo:
A) (a)-(iv), (b)-(iii), (c)-(ii), (d)-(i)
B) (a)-(iii), (b)-(iv), (c)-(ii), (d)-(i)
C) (a)-(ii), (b)-(iii), (c)-(iv), (d)-(i)
D) (a)-(i), (b)-(iii), (c)-(ii), (d)-(iv)
Explanation
[Solution] Carbonyl + HCN gives cyanohydrin; + alcohol gives acetal; + $RNH_2$ gives Schiff's base; + $NH_2OH$ gives oxime. Answer (1).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.