Q. The ratio of the distance traveled by a freely falling body in the $1^{st}$, $2^{nd}$, $3^{rd}$ and $4^{th}$ second :
A) 1 : 1 : 1 : 1
B) 1 : 2 : 3 : 4
C) 1 : 4 : 9 : 16
D) 1 : 3 : 5 : 7
Explanation
[Solution] Distance in the $n^{th}$ second from rest is $\frac{g}{2}(2n-1)$, giving 1 : 3 : 5 : 7. Answer (4).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.