Q. Two resistors of resistance, 100 Ω and 200 Ω are connected in parallel in an electrical circuit. The ratio of the thermal energy developed in 100 Ω to that in 200 Ω in a given time is :
A) 4 : 1
B) 1 : 2
C) 2 : 1
D) 1 : 4
Explanation
[Solution] In parallel, $H = V^2t/R$, so $H_1 : H_2 = R_2 : R_1 = 2 : 1$. Answer (3).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.