Q. In the given nuclear reaction, the element X is : $^{22}_{11}Na \rightarrow X + e^+ + \nu$
A) $^{22}_{12}Mg$
B) $^{22}_{11}Na$
C) $^{22}_{10}Ne$
D) $^{22}_{10}Ne$
Explanation
[Solution] In $\beta^+$ decay A stays the same and Z decreases by 1, so X is $^{22}_{10}Ne$. (Options c and d are printed identically in the source; the source key marks d.) Answer (4).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.