Two pendulums of length 121 cm and 100 cm start vibrating in phase. At some instant, the two are at their means position in the same phase. The minimum number of vibrations of the shorter pendulum after which the two are again in phase at the means position is :

Question

Dr. Abubacker · Accepted Answer

[Solution] $T \propto \sqrt{l}$, so $T_1 : T_2 = 11 : 10$. They are again in phase when the shorter pendulum completes 11 vibrations and the longer one 10. Answer (2).

Q. Two pendulums of length 121 cm and 100 cm start vibrating in phase. At some instant, the two are at their means position in the same phase. The minimum number of vibrations of the shorter pendulum after which the two are again in phase at the means position is :

Explanation

Reviewed by Dr. Abubacker

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