Q. Two transparent media A and B are separated by a plane boundary. The speed of light in those media are $1.5 \times 10^8$ m/s and $2.0 \times 10^8$ m/s, respectively. The critical angle for a ray of light for these two media is :
A) $\tan^{-1}(0.750)$
B) $\sin^{-1}(0.500)$
C) $\sin^{-1}(0.750)$
D) $\tan^{-1}(0.500)$
Explanation
[Solution] $\sin C = \frac{\mu_B}{\mu_A} = \frac{v_A}{v_B} = \frac{1.5}{2.0} = 0.75$, so $C = \sin^{-1}(0.750)$. Answer (3).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.