Q. A particular station of All India Radio, New Delhi, broadcasts on a frequency of 1,368 kHz (kilohertz). The wavelength of the electromagnetic radiation emitted by the transmitter is: [speed of light, $c = 3.0 \times 10^8\ ms^{-1}$]
A) 219.2 m
B) 2192 m
C) 21.92 cm
D) 219.3 m
Explanation
[Solution] $\lambda = c/\nu = 3.0 \times 10^8 / 1.368 \times 10^6 = 219.3$ m. Answer (4).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.