Q. The molar conductance of NaCl, HCl and $CH_3COONa$ at infinite dilution are 126.45, 426.16 and 91.0 S $cm^2$ $mol^{-1}$ respectively. The molar conductance of $CH_3COOH$ at infinite dilution is. Choose the right option for your answer.
A) 390.71 S $cm^2$ $mol^{-1}$
B) 698.28 S $cm^2$ $mol^{-1}$
C) 540.48 S $cm^2$ $mol^{-1}$
D) 201.28 S $cm^2$ $mol^{-1}$
Explanation
[Solution] $\Lambda^\circ_{CH_3COOH} = \Lambda^\circ_{CH_3COONa} + \Lambda^\circ_{HCl} - \Lambda^\circ_{NaCl} = 91.0 + 426.16 - 126.45 = 390.71$ S $cm^2$ $mol^{-1}$. Answer (1).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.