Q. The correct option for the value of vapour pressure of a solution at 45°C with benzene to octane in molar ratio 3 : 2 is: [At 45°C vapour pressure of benzene is 280 mm Hg and that of octane is 420 mm Hg. Assume Ideal gas]
A) 168 mm of Hg
B) 336 mm of Hg
C) 350 mm of Hg
D) 160 mm of Hg
Explanation
[Solution] $P = x_B P_B^\circ + x_O P_O^\circ = 0.6 \times 280 + 0.4 \times 420 = 168 + 168 = 336$ mm Hg. Answer (2).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.