Match List-I with List-II. [table] List-I | List-II ; (A) $[Fe(CN)_6]^{3-}$ | (i) 5.92 BM ; (B) $[Fe(H_2O)_6]^{3+}$ | (ii) 0 BM ; (C) $[Fe(CN)_6]^{4-}$ | (iii) 4.90 BM ; (D) $[Fe(H_2O)_6]^{2+}$ | (iv) 1.73 BM [/table] Choose the correct answer from the options given below.

Question

Dr. Abubacker · Accepted Answer

[Solution] $[Fe(CN)_6]^{3-}$: 1 unpaired e (1.73 BM); $[Fe(H_2O)_6]^{3+}$: 5 (5.92 BM); $[Fe(CN)_6]^{4-}$: 0 (0 BM); $[Fe(H_2O)_6]^{2+}$: 4 (4.90 BM). Answer (3).

Q. Match List-I with List-II. [table] List-I | List-II ; (A) $[Fe(CN)_6]^{3-}$ | (i) 5.92 BM ; (B) $[Fe(H_2O)_6]^{3+}$ | (ii) 0 BM ; (C) $[Fe(CN)_6]^{4-}$ | (iii) 4.90 BM ; (D) $[Fe(H_2O)_6]^{2+}$ | (iv) 1.73 BM [/table] Choose the correct answer from the options given below.

Explanation

Reviewed by Dr. Abubacker

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