Q. If E and G respectively denote energy and gravitational constant, then $\frac{E}{G}$ has the dimensions of:
A) $[M][L^{-1}][T^{-1}]$
B) $[M][L^0][T^0]$
C) $[M^2][L^{-2}][T^{-1}]$
D) $[M^2][L^{-1}][T^0]$
Explanation
[Solution] $[E] = [ML^2T^{-2}]$ and $[G] = [M^{-1}L^3T^{-2}]$, so $[E/G] = [M^2L^{-1}T^0]$. Answer (4).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.