Q. If force [F], acceleration [A] and time [T] are chosen as the fundamental physical quantities. Find the dimensions of energy.
A) [F] [A] $[T^2]$
B) [F] [A] $[T^{-1}]$
C) [F] $[A^{-1}]$ [T]
D) [F] [A] [T]
Explanation
[Solution] Energy = force × distance, and distance has dimensions $[A][T^2]$, so $[E] = [F][A][T^2]$. Answer (1).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.