The escape velocity from the Earth's surface is v. The escape velocity from the surface of another planet having a radius, four times that of Earth and same mass density is:

Question

Dr. Abubacker · Accepted Answer

[Solution] $v_e = \sqrt{2GM/R} \propto R\sqrt{\rho}$; with the same density and 4 times the radius, $v_e$ becomes 4v. Answer (3).

Q. The escape velocity from the Earth's surface is v. The escape velocity from the surface of another planet having a radius, four times that of Earth and same mass density is:

Explanation

Reviewed by Dr. Abubacker

Want to attempt the full paper?