Q. A body is executing simple harmonic motion with frequency 'n', the frequency of its potential energy is:
A) 2n
B) 3n
C) 4n
D) n
Explanation
[Solution] PE $\propto \sin^2\omega t = \frac{1}{2}(1 - \cos 2\omega t)$, so it oscillates at frequency 2n. Answer (1).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.