Q. A spring is stretched by 5 cm by a force 10 N. The time period of the oscillations when a mass of 2 kg is suspended by it is:
A) 6.28 s
B) 3.14 s
C) 0.628 s
D) 0.0628 s
Explanation
[Solution] k = 10/0.05 = 200 N/m; $T = 2\pi\sqrt{m/k} = 2\pi\sqrt{2/200} = 0.628$ s. Answer (3).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.