Q. A capacitor of capacitance 'C', is connected across an ac source of votlage V, given by $V = V_0 \sin \omega t$ The displacement current between the plates of the capacitor, would then be given by:
A) $I_d = \frac{V_0}{\omega C}\cos \omega t$
B) $I_d = \frac{V_0}{\omega C}\sin \omega t$
C) $I_d = V_0\omega C \sin \omega t$
D) $I_d = V_0\omega C \cos \omega t$
Explanation
[Solution] $I_d = C\frac{dV}{dt} = V_0\omega C\cos \omega t$. Answer (4).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.