The number of photons per second on an average emitted by the source of monochromatic light of wavelength 600 nm, when it delivers the power of $3.3 imes 10^{-3}$ watt will be: (h = $6.6 imes 10^{-34}$ Js)

Question

The number of photons per second on an average emitted by the source of monochromatic light of wavelength 600 nm, when it delivers the power of $3.3 	imes 10^{-3}$ watt will be: (h = $6.6 	imes 10^{-34}$ Js)

Dr. Abubacker · Accepted Answer

[Solution] $n = \frac{P\lambda}{hc} = \frac{3.3 	imes 10^{-3} 	imes 6 	imes 10^{-7}}{6.6 	imes 10^{-34} 	imes 3 	imes 10^8} = 10^{16}$ per second. Answer (2).

Q. The number of photons per second on an average emitted by the source of monochromatic light of wavelength 600 nm, when it delivers the power of $3.3 \times 10^{-3}$ watt will be: (h = $6.6 \times 10^{-34}$ Js)

Explanation

Reviewed by Dr. Abubacker

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