Q. The half-life of a radioactive nuclide is 100 hours. The fraction of original activity that will remain after 150 hours would be:
A) $\frac{1}{2\sqrt{2}}$
B) $\frac{2}{3}$
C) $\frac{2}{3\sqrt{2}}$
D) 1/2
Explanation
[Solution] $A/A_0 = (1/2)^{150/100} = (1/2)^{1.5} = \frac{1}{2\sqrt{2}}$. Answer (1).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.