Two conducting circular loops of radii $R_1$ and $R_2$ are placed in the same plane with their centres coinciding. If $R_1 R_2$, the mutual inductance M between them will be directly proportional to:

Question

Two conducting circular loops of radii $R_1$ and $R_2$ are placed in the same plane with their centres coinciding. If $R_1 >> R_2$, the mutual inductance M between them will be directly proportional to:

Dr. Abubacker · Accepted Answer

[Solution] $\phi_2 = \frac{\mu_0 I}{2R_1}\pi R_2^2$, so $M = \frac{\mu_0\pi R_2^2}{2R_1} \propto R_2^2/R_1$. Answer (3).

Q. Two conducting circular loops of radii $R_1$ and $R_2$ are placed in the same plane with their centres coinciding. If $R_1 >> R_2$, the mutual inductance M between them will be directly proportional to:

Explanation

Reviewed by Dr. Abubacker

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