Q. In a cross between a male and female, both heterozygous for sickle cell anaemia gene, what percentage of the progeny will be diseased?
A) 75%
B) 25%
C) 100%
D) 50%
Explanation
[Solution] $Hb^AHb^S \times Hb^AHb^S$ gives 1 $Hb^AHb^A$ : 2 $Hb^AHb^S$ : 1 $Hb^SHb^S$; 25% are diseased. Answer (2).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.