Q. The average thermal energy for a mono-atomic gas is : ($k_B$ is Boltzmann constant and T, absolute temperature)

A) $\frac{3}{2}k_BT$
B) $\frac{5}{2}k_BT$
C) $\frac{7}{2}k_BT$
D) $\frac{1}{2}k_BT$
Explanation

[Solution] A monatomic molecule has 3 translational degrees of freedom: $\frac{3}{2}k_BT$. Answer (1).

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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