Q. The mean free path for a gas, with molecular diameter d and number density n can be expressed as :
A) $\frac{1}{\sqrt{2}n\pi d^2}$
B) $\frac{1}{\sqrt{2}n^2\pi d^2}$
C) $\frac{1}{\sqrt{2}n^2\pi^2d^2}$
D) $\frac{1}{\sqrt{2}n\pi d}$
Explanation
[Solution] $\lambda = \frac{1}{\sqrt{2}n\pi d^2}$. Answer (1).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.