Q. A charged particle having drift velocity of $7.5 \times 10^{-4}$ m $s^{-1}$ in an electric field of $3 \times 10^{-10}$ V $m^{-1}$, has a mobility in $m^2$ $V^{-1}$ $s^{-1}$ of :

A) $2.5 \times 10^6$
B) $2.5 \times 10^{-6}$
C) $2.25 \times 10^{-15}$
D) $2.25 \times 10^{15}$
Explanation

[Solution] $\mu = v_d/E = 7.5 \times 10^{-4} / 3 \times 10^{-10} = 2.5 \times 10^6$. Answer (1).

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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