Q. In Young's double slit experiment, if the separation between coherent sources is halved and the distance of the screen from the coherent sources is doubled, then the fringe width becomes :
A) half
B) four times
C) one-fourth
D) double
Explanation
[Solution] $\beta = \lambda D/d$; D doubled and d halved makes $\beta$ four times. Answer (2).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.