Q. A ball is thrown vertically downward with a velocity of 20 m/s from the top of a tower. It hits the ground after some time with a velocity of 80 m/s. The height of the tower is : (g = 10 $m/s^2$)

A) 340 m
B) 320 m
C) 300 m
D) 360 m
Explanation

[Solution] $v^2 = u^2 + 2gh$: $6400 = 400 + 20h$, so h = 300 m. Answer (3).

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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