Q. A 40 μF capacitor is connected to a 200 V, 50 Hz ac supply. The rms value of the current in the circuit is, nearly :
A) 2.05 A
B) 2.5 A
C) 25.1 A
D) 1.7 A
Explanation
[Solution] $I = V\omega C = 200 \times 2\pi \times 50 \times 40 \times 10^{-6} = 2.51$ A. Answer (2).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.