A short electric dipole has a dipole moment of $16 imes 10^{-9}$ C m. The electric potential due to the dipole at a point at a distance of 0.6 m from the centre of the dipole, situated on a line making an angle of 60° with the dipole axis is : ($\frac{1}{4\pi\epsilon_0} = 9 imes 10^9$ N $m^2/C^2$)

Question

A short electric dipole has a dipole moment of $16 	imes 10^{-9}$ C m. The electric potential due to the dipole at a point at a distance of 0.6 m from the centre of the dipole, situated on a line making an angle of 60° with the dipole axis is : ($\frac{1}{4\pi\epsilon_0} = 9 	imes 10^9$ N $m^2/C^2$)

Dr. Abubacker · Accepted Answer

[Solution] $V = \frac{kp\cos	heta}{r^2} = \frac{9 	imes 10^9 	imes 16 	imes 10^{-9} 	imes 0.5}{0.36} = 200$ V. Answer (1).

Explanation

Reviewed by Dr. Abubacker

Want to attempt the full paper?