Q. In a guitar, two strings A and B made of same material are slightly out of tune and produce beats of frequency 6 Hz. When tension in B is slightly decreased, the beat frequency increases to 7 Hz. If the frequency of A is 530 Hz, the original frequency of B will be :

A) 524 Hz
B) 536 Hz
C) 537 Hz
D) 523 Hz
Explanation

[Solution] $f_B$ = 524 or 536 Hz. Lowering tension lowers $f_B$; the beat frequency rises only if $f_B$ was below $f_A$, so $f_B$ = 524 Hz. Answer (1).

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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