Q. An electron is accelerated from rest through a potential difference of V volt. If the de Broglie wavelength of the electron is $1.227 \times 10^{-2}$ nm, the potential difference is :
A) $10^2$ V
B) $10^3$ V
C) $10^4$ V
D) 10 V
Explanation
[Solution] $\lambda = \frac{1.227}{\sqrt{V}}$ nm gives $\sqrt{V} = 100$, so V = $10^4$ V. Answer (3).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.