Q. What is the change in oxidation number of carbon in the following reaction ? $CH_4(g) + 4Cl_2(g) \rightarrow CCl_4(l) + 4HCl(g)$
A) 0 to +4
B) -4 to +4
C) 0 to -4
D) +4 to +4
Explanation
[Solution] C is -4 in $CH_4$ and +4 in $CCl_4$. Answer (2).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.