Q. The rate constant for a first order reaction is $4.606 \times 10^{-3}$ $s^{-1}$. The time required to reduce 2.0 g of the reactant to 0.2 g is :

A) 200 s
B) 500 s
C) 1000 s
D) 100 s
Explanation

[Solution] $t = \frac{2.303}{k}\log\frac{2.0}{0.2} = \frac{2.303}{4.606 \times 10^{-3}} = 500$ s. Answer (2).

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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