Q. The calculated spin only magnetic moment of $Cr^{2+}$ ion is :
A) 4.90 BM
B) 5.92 BM
C) 2.84 BM
D) 3.87 BM
Explanation
[Solution] $Cr^{2+}$ ($3d^4$) has 4 unpaired electrons: $\mu = \sqrt{4 \times 6} = 4.90$ BM. Answer (1).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.